What is (\partial)/(\partial x)(yz+xln(y)-z^2) ?

The answer to (\partial)/(\partial x)(yz+xln(y)-z^2) is ln(y)

Popular >

(\partial)/(\partial x)(yz+xln(y)-z^2)

\frac{\partial}{\partial x} (yz + x ln (y) - z^{2})

ln (y)

Solution steps

\frac{\partial}{\partial x} (yz + x ln (y) - z^{2})

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (yz) + \frac{\partial}{\partial x} (x ln (y)) - \frac{\partial}{\partial x} (z^{2})

\frac{\partial}{\partial x} (yz) = 0

\frac{\partial}{\partial x} (x ln (y)) = ln (y)

\frac{\partial}{\partial x} (z^{2}) = 0

= 0 + ln (y) - 0

Simplify

= ln (y)

\frac{3}{x + 2}

n = 1 \sum \infty \frac{1}{( 2 n - 1 ) ^{4}}

\frac{d}{d x} ((e^{(x^{2})} + 4)^{2})

y^{^{''}} - 8 y^{^{'}} + 18 y = 0, y (0) = 1, y^{^{'}} (0) = - 4

\int (8 x^{2} + 5)^{10} x d x

What is (\partial)/(\partial x)(yz+xln(y)-z^2) ?
The answer to (\partial)/(\partial x)(yz+xln(y)-z^2) is ln(y)