What is the sum from n=1 to infinity of 1/((2n-1)^4) ?

The sum from n=1 to infinity of 1/((2n-1)^4) is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity of 1/((2n-1)^4)

n = 1 \sum \infty \frac{1}{( 2 n - 1 ) ^{4}}

converges

Solution steps

n = 1 \sum \infty \frac{1}{( 2 n - 1 ) ^{4}}

Apply Series Integral Test:

converges

= converges

\frac{d}{d x} ((e^{(x^{2})} + 4)^{2})

y^{^{''}} - 8 y^{^{'}} + 18 y = 0, y (0) = 1, y^{^{'}} (0) = - 4

\int (8 x^{2} + 5)^{10} x d x

\int 2 x (x^{2} + 7)^{7} d x

\frac{d y}{d x} = - \frac{1}{3} x^{3}

What is the sum from n=1 to infinity of 1/((2n-1)^4) ?
The sum from n=1 to infinity of 1/((2n-1)^4) is converges