What is (\partial)/(\partial t)(t/(2y^4)) ?

The answer to (\partial)/(\partial t)(t/(2y^4)) is 1/(2y^4)

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(\partial)/(\partial t)(t/(2y^4))

\frac{\partial}{\partial t} (\frac{t}{2 y ^{4}})

\frac{1}{2 y ^{4}}

Solution steps

\frac{\partial}{\partial t} (\frac{t}{2 y ^{4}})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2 y ^{4}} \frac{\partial}{\partial t} (t)

Apply the common derivative:

\frac{\partial}{\partial t} (t) = 1

= \frac{1}{2 y ^{4}} \cdot 1

Simplify

= \frac{1}{2 y ^{4}}

x \to 0 - lim (\frac{1}{2 + e ^{\frac{1}{x}}})

\int_{0}^{2} 2 x - x^{2} d x

9 x, x^{2} - 10

\frac{\partial}{\partial x} (yz + x ln (y) - z^{2})

\frac{3}{x + 2}

What is (\partial)/(\partial t)(t/(2y^4)) ?
The answer to (\partial)/(\partial t)(t/(2y^4)) is 1/(2y^4)