What is the derivative of \sqrt[3]{x-3} ?

The derivative of \sqrt[3]{x-3} is 1/(3(x-3)^{2/3)}

What is the first derivative of \sqrt[3]{x-3} ?

The first derivative of \sqrt[3]{x-3} is 1/(3(x-3)^{2/3)}

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\frac{1}{3 ( x - 3 ) ^{\frac{2}{3}}}

Solution steps

Apply the chain rule:

\frac{1}{3 ( x - 3 ) ^{\frac{2}{3}}} \frac{d}{d x} (x - 3)

= \frac{1}{3 ( x - 3 ) ^{\frac{2}{3}}} \frac{d}{d x} (x - 3)

\frac{d}{d x} (x - 3) = 1

= \frac{1}{3 ( x - 3 ) ^{\frac{2}{3}}} \cdot 1

Simplify

= \frac{1}{3 ( x - 3 ) ^{\frac{2}{3}}}

3 x^{4} - 3 x^{2}, 6 x^{2}

\frac{\partial}{\partial t} (\frac{t}{2 y ^{4}})

x \to 0 - lim (\frac{1}{2 + e ^{\frac{1}{x}}})

\int_{0}^{2} 2 x - x^{2} d x

9 x, x^{2} - 10

What is the derivative of \sqrt[3]{x-3} ?
The derivative of \sqrt[3]{x-3} is 1/(3(x-3)^{2/3)}
What is the first derivative of \sqrt[3]{x-3} ?
The first derivative of \sqrt[3]{x-3} is 1/(3(x-3)^{2/3)}