What is the solution for 2x^3dy=y(2x^2-y^3)dx ?

The solution for 2x^3dy=y(2x^2-y^3)dx is y=(\sqrt[3]{2}x)/(\sqrt[3]{3x+c_{1)}}

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2x^3dy=y(2x^2-y^3)dx

2 x^{3} d y = y (2 x^{2} - y^{3}) d x

Solution steps

2 x^{3} d y = y (2 x^{2} - y^{3}) d x

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What is the solution for 2x^3dy=y(2x^2-y^3)dx ?
The solution for 2x^3dy=y(2x^2-y^3)dx is y=(\sqrt[3]{2}x)/(\sqrt[3]{3x+c_{1)}}