What is the integral of cos^3(t)sin(t) ?

The integral of cos^3(t)sin(t) is -(cos^4(t))/4+C

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integral of cos^3(t)sin(t)

\int cos^{3} (t) sin (t) d t

- \frac{cos ^{4} ( t )}{4} + C

Solution steps

\int cos^{3} (t) sin (t) d t

Apply u-substitution

: \int - u^{3} d u

= \int - u^{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int u^{3} d u

Apply the Power Rule

: \frac{u ^{4}}{4}

= - \frac{u ^{4}}{4}

Substitute back

u = cos (t)

= - \frac{cos ^{4} ( t )}{4}

Add a constant to the solution

= - \frac{cos ^{4} ( t )}{4} + C

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What is the integral of cos^3(t)sin(t) ?
The integral of cos^3(t)sin(t) is -(cos^4(t))/4+C