What is the tangent of y=4e^x+x,(0,4) ?

The tangent of y=4e^x+x,(0,4) is y=5x+4

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tangent of y=4e^x+x,(0,4)

tangent of

y = 4 e^{x} + x, (0, 4)

y = 5 x + 4

Solution steps

Find the slope of

y = 4 e^{x} + x : \frac{d y}{d x} = 4 e^{x} + 1

Compute the slope of

y = 4 e^{x} + x

(0, 4) : m = 5

Find the line with slope m=

5

and passing through

(0, 4) : y = 5 x + 4

y = 5 x + 4

\int_{- π}^{π} x \cdot sin (n \cdot x) d x

\int - sin (x) sec (x) tan (x) d x

\int 4 x^{3} - \frac{3}{x ^{4}} d x

3 - 9 x

\frac{d}{d x} (4 x - \frac{3}{x} + \frac{1}{x ^{2}})