What is the derivative of (x^2)/4+x+1 ?

The derivative of (x^2)/4+x+1 is x/2+1

What is the first derivative of (x^2)/4+x+1 ?

The first derivative of (x^2)/4+x+1 is x/2+1

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derivative of

\frac{x ^{2}}{4} + x + 1

\frac{x}{2} + 1

Solution steps

\frac{d}{d x} (\frac{x ^{2}}{4} + x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{2}}{4}) + \frac{d x}{d x} + \frac{d}{d x} (1)

\frac{d}{d x} (\frac{x ^{2}}{4}) = \frac{x}{2}

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= \frac{x}{2} + 1 + 0

Simplify

= \frac{x}{2} + 1

\int \frac{1}{sin ( x ) - 2 csc ( x )} d x

y = \frac{5 x}{x - 2}, (3, 15)

f (x) = \frac{x ^{2}}{x + 4}

\int (6 e^{x}) d x

n = 0 \sum \infty \frac{7}{2 ^{n}}

What is the derivative of (x^2)/4+x+1 ?
The derivative of (x^2)/4+x+1 is x/2+1
What is the first derivative of (x^2)/4+x+1 ?
The first derivative of (x^2)/4+x+1 is x/2+1