What is the tangent of y=(5x)/(x-2),(3,15) ?

The tangent of y=(5x)/(x-2),(3,15) is y=-10x+45

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tangent of y=(5x)/(x-2),(3,15)

tangent of

y = \frac{5 x}{x - 2}, (3, 15)

y = - 10 x + 45

Solution steps

Find the slope of

y = \frac{5 x}{x - 2} : \frac{d y}{d x} = - \frac{10}{( x - 2 ) ^{2}}

Compute the slope of

y = \frac{5 x}{x - 2}

(3, 15) : m = - 10

Find the line with slope m=

- 10

and passing through

(3, 15) : y = - 10 x + 45

y = - 10 x + 45

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What is the tangent of y=(5x)/(x-2),(3,15) ?
The tangent of y=(5x)/(x-2),(3,15) is y=-10x+45