en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'+1=2y

Solution

y^{^{'}} + 1 = 2 y

Solution

y = \frac{e ^{2 t + c_{1}}}{2} + \frac{1}{2}

Solution steps

y^{'} (t) + 1 = 2 y

Solve separable ODE:

y = \frac{e ^{2 t + c_{1}}}{2} + \frac{1}{2}

y = \frac{e ^{2 t + c_{1}}}{2} + \frac{1}{2}

Popular Examples

integral of x/((x^2-4)^3)

\int \frac{x}{( x ^{2} - 4 ) ^{3}} d x

derivative of (ax^2/(ln(x/4)))

\frac{d}{d x} (\frac{a x ^{2}}{ln ( \frac{x}{4} )})

y^{^{'}} = \frac{x - y}{x}

derivative of e^{-(x+2)}-sin(x^2)+1 derivative of

e^{- (x + 2)} - sin (x^{2}) + 1

derivative of (x^2)/4+x+1 derivative of

\frac{x ^{2}}{4} + x + 1

Frequently Asked Questions (FAQ)

What is the solution for y^'+1=2y ?
The solution for y^'+1=2y is y=(e^{2t+c_{1}})/2+1/2