What is the derivative of ln(e^{x^2}) ?

The derivative of ln(e^{x^2}) is 2x

What is the first derivative of ln(e^{x^2}) ?

The first derivative of ln(e^{x^2}) is 2x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

ln (e^{x^{2}})

2 x

Solution steps

\frac{d}{d x} (ln (e^{x^{2}}))

Simplify

ln (e^{x^{2}}) : x^{2}

= \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 x^{2 - 1}

Simplify

= 2 x

\int \frac{x ^{2}}{x ^{2} - 4 x + 13} d x

\int \frac{e ^{4 x}}{2} d x

x \to 0 lim (x \cdot ln (x))

x \to 3 lim (4^{f (x)})

\int_{1}^{2 x} \frac{y}{x} d x

What is the derivative of ln(e^{x^2}) ?
The derivative of ln(e^{x^2}) is 2x
What is the first derivative of ln(e^{x^2}) ?
The first derivative of ln(e^{x^2}) is 2x