What is the solution for (dy)/(dx)+(4/x)y=-4x-5 ?

The solution for (dy)/(dx)+(4/x)y=-4x-5 is y=-(2x^2)/3-x+(c_{1})/(x^4)

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(dy)/(dx)+(4/x)y=-4x-5

\frac{d y}{d x} + (\frac{4}{x}) y = - 4 x - 5

y = - \frac{2 x ^{2}}{3} - x + \frac{c _{1}}{x ^{4}}

Solution steps

\frac{d y}{d x} + (\frac{4}{x}) y = - 4 x - 5

Solve linear ODE:

y = - \frac{2 x ^{2}}{3} - x + \frac{c _{1}}{x ^{4}}

y = - \frac{2 x ^{2}}{3} - x + \frac{c _{1}}{x ^{4}}

\int_{0}^{1} \frac{1}{x ( x + 1 )} d x

\frac{\partial}{\partial x} (4 x^{4} y^{5} - 3 x^{2})

\frac{\partial}{\partial x} (x - y^{2} + 3 x y)

\int (\frac{1}{x ^{2} + 9}) d x

y = \frac{( x - 5 )}{x ^{3}}

What is the solution for (dy)/(dx)+(4/x)y=-4x-5 ?
The solution for (dy)/(dx)+(4/x)y=-4x-5 is y=-(2x^2)/3-x+(c_{1})/(x^4)