What is (\partial)/(\partial x)(4x^4y^5-3x^2) ?

The answer to (\partial)/(\partial x)(4x^4y^5-3x^2) is 16y^5x^3-6x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(4x^4y^5-3x^2)

\frac{\partial}{\partial x} (4 x^{4} y^{5} - 3 x^{2})

16 y^{5} x^{3} - 6 x

Solution steps

\frac{\partial}{\partial x} (4 x^{4} y^{5} - 3 x^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (4 x^{4} y^{5}) - \frac{\partial}{\partial x} (3 x^{2})

\frac{\partial}{\partial x} (4 x^{4} y^{5}) = 16 y^{5} x^{3}

\frac{\partial}{\partial x} (3 x^{2}) = 6 x

= 16 y^{5} x^{3} - 6 x

\frac{\partial}{\partial x} (x - y^{2} + 3 x y)

\int (\frac{1}{x ^{2} + 9}) d x

y = \frac{( x - 5 )}{x ^{3}}

\frac{d}{d x} (\frac{1}{2 x + 2})

(- 3.3) (5.9)

What is (\partial)/(\partial x)(4x^4y^5-3x^2) ?
The answer to (\partial)/(\partial x)(4x^4y^5-3x^2) is 16y^5x^3-6x