What is the slope of (-2/7 , 2/3),(5/7 ,-7/3) ?

The slope of (-2/7 , 2/3),(5/7 ,-7/3) is m=-3

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slope of (-2/7 , 2/3),(5/7 ,-7/3)

slope

(- \frac{2}{7}, \frac{2}{3}), (\frac{5}{7}, - \frac{7}{3})

m = - 3

Solution steps

Slope between two points: Slope

= \frac{y _{2} - y _{1}}{x _{2} - x _{1}}

(x_{1}, y_{1}) = (- \frac{2}{7}, \frac{2}{3}), (x_{2}, y_{2}) = (\frac{5}{7}, - \frac{7}{3})

m = \frac{- \frac{7}{3} - \frac{2}{3}}{\frac{5}{7} - ( - \frac{2}{7} )}

Refine

m = - 3

x \to 1 lim (\frac{x - 1}{x ^{n} - 1})

(x + y)^{2} d x + (2 x y + x^{2} - 4) d y = 0

\frac{d}{d x} (5 e^{x} + 3)

\frac{d}{d x} ((x^{2} + 4) e^{- 2 x})

(x^{2} - 1) (\frac{d y}{d x}) = 2 y

What is the slope of (-2/7 , 2/3),(5/7 ,-7/3) ?
The slope of (-2/7 , 2/3),(5/7 ,-7/3) is m=-3