What is area e^x,e^{-x},[0,1] ?

The answer to area e^x,e^{-x},[0,1] is (e^2+1)/e-2

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area e^x,e^{-x},[0,1]

area

e^{x}, e^{- x}, [0, 1]

\frac{e ^{2} + 1}{e} - 2

Decimal Notation

1.08616 \dots

Solution steps

Apply the area formula:

\int_{0}^{1} e^{x} - e^{- x} d x

Solve

\int_{0}^{1} e^{x} - e^{- x} d x : \frac{e ^{2} + 1}{e} - 2

The area is:

= \frac{e ^{2} + 1}{e} - 2

\frac{\partial}{\partial x} ((x^{3} - y^{2})^{- 1})

x \to 0 + lim ((1 + x)^{(\frac{1}{x})})

\frac{d}{d x} (25 x^{3} - 6 x^{2} + 7 x - 88)

\frac{d y}{d x} = 0.1 y (1 - \frac{y}{500})

9 y^{^{''}} - 24 y^{^{'}} + 16 y = 0

What is area e^x,e^{-x},[0,1] ?
The answer to area e^x,e^{-x},[0,1] is (e^2+1)/e-2