What is the derivative of 25x^3-6x^2+7x-88 ?

The derivative of 25x^3-6x^2+7x-88 is 75x^2-12x+7

What is the first derivative of 25x^3-6x^2+7x-88 ?

The first derivative of 25x^3-6x^2+7x-88 is 75x^2-12x+7

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\frac{d}{d x} (25 x^{3} - 6 x^{2} + 7 x - 88)

75 x^{2} - 12 x + 7

Solution steps

\frac{d}{d x} (25 x^{3} - 6 x^{2} + 7 x - 88)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (25 x^{3}) - \frac{d}{d x} (6 x^{2}) + \frac{d}{d x} (7 x) - \frac{d}{d x} (88)

\frac{d}{d x} (25 x^{3}) = 75 x^{2}

\frac{d}{d x} (6 x^{2}) = 12 x

\frac{d}{d x} (7 x) = 7

\frac{d}{d x} (88) = 0

= 75 x^{2} - 12 x + 7 - 0

Simplify

= 75 x^{2} - 12 x + 7

What is the derivative of 25x^3-6x^2+7x-88 ?
The derivative of 25x^3-6x^2+7x-88 is 75x^2-12x+7
What is the first derivative of 25x^3-6x^2+7x-88 ?
The first derivative of 25x^3-6x^2+7x-88 is 75x^2-12x+7