en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6y^'=y^2,y(0)=5

Solution

6 y^{^{'}} = y^{2}, y (0) = 5

Solution

y = - \frac{30}{5 t - 6}

Solution steps

6 y^{'} (t) = y^{2}

Solve separable ODE:

y = - \frac{30}{5 t - 6}

y = - \frac{30}{5 t - 6}

Popular Examples

(2 x - 1)^{^{'}}

integral of (x^2)/((4-x^2)^{3/2)}

\int \frac{x ^{2}}{( 4 - x ^{2} ) ^{\frac{3}{2}}} d x

derivative of y=e^xsin(x)derivative of

y = e^{x} sin (x)

derivative of f(x)=6x^6(x^4-6x)derivative of

f (x) = 6 x^{6} (x^{4} - 6 x)

tangent of f(x)=e^x,\at x=ln(3)tangent of

f (x) = e^{x}, at x = ln (3)

Frequently Asked Questions (FAQ)

What is the solution for 6y^'=y^2,y(0)=5 ?
The solution for 6y^'=y^2,y(0)=5 is y=-(30)/(5t-6)