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Popular >

(2x-1)^'

Solution

(2 x - 1)^{^{'}}

Solution

2

Solution steps

(2 x - 1)^{'}

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= (2 x)^{^{'}} - 1^{^{'}}

(2 x)^{'} = 2

1^{'} = 0

= 2 - 0

Simplify

= 2

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Frequently Asked Questions (FAQ)

What is the (2x-1)^' ?
The (2x-1)^' is 2
What is the first (2x-1)^' ?
The first (2x-1)^' is 2