What is (\partial)/(\partial x)(sin(4x-2y)) ?

The answer to (\partial)/(\partial x)(sin(4x-2y)) is cos(4x-2y)*4

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(\partial)/(\partial x)(sin(4x-2y))

\frac{\partial}{\partial x} (sin (4 x - 2 y))

cos (4 x - 2 y) \cdot 4

Solution steps

\frac{\partial}{\partial x} (sin (4 x - 2 y))

Treat

y

as a constant

Apply the chain rule:

cos (4 x - 2 y) \frac{\partial}{\partial x} (4 x - 2 y)

= cos (4 x - 2 y) \frac{\partial}{\partial x} (4 x - 2 y)

\frac{\partial}{\partial x} (4 x - 2 y) = 4

= cos (4 x - 2 y) \cdot 4

\frac{d}{d x} (\frac{x}{e ^{x} + 1})

\frac{\partial}{\partial x} (x e^{- 3 x y})

n = 1 \sum \infty \frac{n}{3}

\frac{d}{d x} (\frac{3 x - 4}{6 x ^{2} - 1})

f (x) = ln (5 x - 7)

What is (\partial)/(\partial x)(sin(4x-2y)) ?
The answer to (\partial)/(\partial x)(sin(4x-2y)) is cos(4x-2y)*4