What is the integral from 1 to 2 of (3/x) ?

The integral from 1 to 2 of (3/x) is 3ln(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 2 of (3/x)

\int_{1}^{2} (\frac{3}{x}) d x

3 ln (2)

Decimal Notation

2.07944 \dots

Solution steps

\int_{1}^{2} \frac{3}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{1}^{2} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= 3 [ln ∣ x ∣]_{1}^{2}

Compute the boundaries:

ln (2)

= 3 ln (2)

\frac{d}{d x} (\frac{- 5}{x})

\int \frac{1}{x ^{- 2}} d x

n = 6 \sum \infty e^{7 - 6 n}

\frac{\partial}{\partial x} ((x - y)^{2})

\frac{\partial}{\partial y} (- \frac{1}{y} sin (\frac{x}{y}))

What is the integral from 1 to 2 of (3/x) ?
The integral from 1 to 2 of (3/x) is 3ln(2)