What is the sum from n=6 to infinity of e^{7-6n} ?

The sum from n=6 to infinity of e^{7-6n} is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=6 to infinity of e^{7-6n}

n = 6 \sum \infty e^{7 - 6 n}

converges

Solution steps

n = 6 \sum \infty e^{7 - 6 n}

Apply Series Ratio Test:

converges

= converges

\frac{\partial}{\partial x} ((x - y)^{2})

\frac{\partial}{\partial y} (- \frac{1}{y} sin (\frac{x}{y}))

\frac{d ^{2}}{d x ^{2}} (\frac{5}{6 x ^{4}})

\frac{d}{d x} ((x - 1) sin (x))

\frac{\partial}{\partial x} (ln (e^{x} + e^{y}))

What is the sum from n=6 to infinity of e^{7-6n} ?
The sum from n=6 to infinity of e^{7-6n} is converges