What is the integral of sin(x)cos(3x) ?

The integral of sin(x)cos(3x) is 1/2 (-1/4 cos(4x)+1/2 cos(2x))+C

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integral of sin(x)cos(3x)

\int sin (x) cos (3 x) d x

\frac{1}{2} (- \frac{1}{4} cos (4 x) + \frac{1}{2} cos (2 x)) + C

Solution steps

\int sin (x) cos (3 x) d x

Use the following identity:

cos (t) sin (s) = \frac{sin ( s + t ) + sin ( s - t )}{2}

= \int \frac{sin ( x + 3 x ) + sin ( x - 3 x )}{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int sin (x + 3 x) + sin (x - 3 x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} (\int sin (x + 3 x) d x + \int sin (x - 3 x) d x)

\int sin (x + 3 x) d x = - \frac{1}{4} cos (4 x)

\int sin (x - 3 x) d x = \frac{1}{2} cos (2 x)

= \frac{1}{2} (- \frac{1}{4} cos (4 x) + \frac{1}{2} cos (2 x))

Add a constant to the solution

= \frac{1}{2} (- \frac{1}{4} cos (4 x) + \frac{1}{2} cos (2 x)) + C

x \to 1 lim (x^{(\frac{1}{x - 1})})

x \to x lim (\frac{1}{x})

x \to 0 - lim (\frac{3 x - 1}{2 x})

\int \frac{x}{a x ^{2} + b} d x

\int cot (23 x) d x

What is the integral of sin(x)cos(3x) ?
The integral of sin(x)cos(3x) is 1/2 (-1/4 cos(4x)+1/2 cos(2x))+C