What is the derivative of f(x)=9e^x+4/(\sqrt[3]{x)} ?

The derivative of f(x)=9e^x+4/(\sqrt[3]{x)} is 9e^x-4/(3x^{4/3)}

What is the first derivative of f(x)=9e^x+4/(\sqrt[3]{x)} ?

The first derivative of f(x)=9e^x+4/(\sqrt[3]{x)} is 9e^x-4/(3x^{4/3)}

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derivative of

9 e^{x} - \frac{4}{3 x ^{\frac{4}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (9 e^{x}) = 9 e^{x}

= 9 e^{x} - \frac{4}{3 x ^{\frac{4}{3}}}

\frac{\partial}{\partial y} (arctan (9 x - 9 y))

\int sin (x) cos (3 x) d x

x \to 1 lim (x^{(\frac{1}{x - 1})})

x \to x lim (\frac{1}{x})

x \to 0 - lim (\frac{3 x - 1}{2 x})

What is the derivative of f(x)=9e^x+4/(\sqrt[3]{x)} ?
The derivative of f(x)=9e^x+4/(\sqrt[3]{x)} is 9e^x-4/(3x^{4/3)}
What is the first derivative of f(x)=9e^x+4/(\sqrt[3]{x)} ?
The first derivative of f(x)=9e^x+4/(\sqrt[3]{x)} is 9e^x-4/(3x^{4/3)}