What is the derivative of (x^{-1/2}+2x(7-x^{-1})) ?

The derivative of (x^{-1/2}+2x(7-x^{-1})) is (-1/(2x^{3/2)}+2)(7-1/x)+(1+2x^{3/2})/(x^{5/2)}

What is the first derivative of (x^{-1/2}+2x(7-x^{-1})) ?

The first derivative of (x^{-1/2}+2x(7-x^{-1})) is (-1/(2x^{3/2)}+2)(7-1/x)+(1+2x^{3/2})/(x^{5/2)}

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\frac{d}{d x} ((x^{- \frac{1}{2}} + 2 x) (7 - x^{- 1}))

(- \frac{1}{2 x ^{\frac{3}{2}}} + 2) (7 - \frac{1}{x}) + \frac{1 + 2 x ^{\frac{3}{2}}}{x ^{\frac{5}{2}}}

Solution steps

\frac{d}{d x} ((x^{- \frac{1}{2}} + 2 x) (7 - x^{- 1}))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{- \frac{1}{2}} + 2 x, g = 7 - x^{- 1}

= \frac{d}{d x} (x^{- \frac{1}{2}} + 2 x) (7 - x^{- 1}) + \frac{d}{d x} (7 - x^{- 1}) (x^{- \frac{1}{2}} + 2 x)

\frac{d}{d x} (x^{- \frac{1}{2}} + 2 x) = - \frac{1}{2 x ^{\frac{3}{2}}} + 2

\frac{d}{d x} (7 - x^{- 1}) = \frac{1}{x ^{2}}

= (- \frac{1}{2 x ^{\frac{3}{2}}} + 2) (7 - x^{- 1}) + \frac{1}{x ^{2}} (x^{- \frac{1}{2}} + 2 x)

Simplify

(- \frac{1}{2 x ^{\frac{3}{2}}} + 2) (7 - x^{- 1}) + \frac{1}{x ^{2}} (x^{- \frac{1}{2}} + 2 x) : (- \frac{1}{2 x ^{\frac{3}{2}}} + 2) (7 - \frac{1}{x}) + \frac{1 + 2 x ^{\frac{3}{2}}}{x ^{\frac{5}{2}}}

= (- \frac{1}{2 x ^{\frac{3}{2}}} + 2) (7 - \frac{1}{x}) + \frac{1 + 2 x ^{\frac{3}{2}}}{x ^{\frac{5}{2}}}

f (x) = - 4 x + 5

\frac{1}{x - 5}

y = \frac{1}{x - 6}, (5, - 1)

\int x^{- 5} + x^{\frac{1}{2}} d x

\frac{d}{d x} ((- x^{2} + 25)^{2})

What is the derivative of (x^{-1/2}+2x(7-x^{-1})) ?
The derivative of (x^{-1/2}+2x(7-x^{-1})) is (-1/(2x^{3/2)}+2)(7-1/x)+(1+2x^{3/2})/(x^{5/2)}
What is the first derivative of (x^{-1/2}+2x(7-x^{-1})) ?
The first derivative of (x^{-1/2}+2x(7-x^{-1})) is (-1/(2x^{3/2)}+2)(7-1/x)+(1+2x^{3/2})/(x^{5/2)}