What is the tangent of y= 1/(x-6),(5,-1) ?

The tangent of y= 1/(x-6),(5,-1) is y=-x+4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y= 1/(x-6),(5,-1)

tangent of

y = \frac{1}{x - 6}, (5, - 1)

y = - x + 4

Solution steps

Find the slope of

y = \frac{1}{x - 6} : \frac{d y}{d x} = - \frac{1}{( x - 6 ) ^{2}}

Compute the slope of

y = \frac{1}{x - 6}

(5, - 1) : m = - 1

Find the line with slope m=

- 1

and passing through

(5, - 1) : y = - x + 4

y = - x + 4

\int x^{- 5} + x^{\frac{1}{2}} d x

\frac{d}{d x} ((- x^{2} + 25)^{2})

\int \frac{7}{x ^{3} - 125} d x

\frac{\partial}{\partial y} (sin^{2} (x - 3 y))

\frac{d}{d x} (s cos (x))

What is the tangent of y= 1/(x-6),(5,-1) ?
The tangent of y= 1/(x-6),(5,-1) is y=-x+4