What is the limit as x approaches infinity of-1/x+1 ?

The limit as x approaches infinity of-1/x+1 is 1

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limit as x approaches infinity of-1/x+1

x \to \infty lim (- \frac{1}{x} + 1)

1

Solution steps

x \to \infty lim (- \frac{1}{x} + 1)

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= - x \to \infty lim (\frac{1}{x}) + x \to \infty lim (1)

x \to \infty lim (\frac{1}{x}) = 0

x \to \infty lim (1) = 1

= - 0 + 1

Simplify

= 1

f (x) = ln (\frac{4 + x ^{2}}{x})

f (x) = 20 x, (4, 40)

y^{^{''}} + 5 y^{^{'}} - 2 y = 0

\int \frac{1}{t ^{2} - 12 t + 40} d t

x \to 0 - lim \frac{1}{\frac{1}{x}}

What is the limit as x approaches infinity of-1/x+1 ?
The limit as x approaches infinity of-1/x+1 is 1