What is the integral of (3x)/(x+2) ?

The integral of (3x)/(x+2) is 3(x+2-2ln|x+2|)+C

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integral of (3x)/(x+2)

\int \frac{3 x}{x + 2} d x

3 (x + 2 - 2 ln ∣ x + 2 ∣) + C

Solution steps

\int \frac{3 x}{x + 2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int \frac{x}{x + 2} d x

Apply u-substitution

: \int \frac{u - 2}{u} d u

= 3 \cdot \int \frac{u - 2}{u} d u

Expand

\frac{u - 2}{u} : 1 - \frac{2}{u}

= 3 \cdot \int 1 - \frac{2}{u} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 3 (\int 1 d u - \int \frac{2}{u} d u)

\int 1 d u = u

\int \frac{2}{u} d u = 2 ln ∣ u ∣

= 3 (u - 2 ln ∣ u ∣)

Substitute back

u = x + 2

= 3 (x + 2 - 2 ln ∣ x + 2 ∣)

Add a constant to the solution

= 3 (x + 2 - 2 ln ∣ x + 2 ∣) + C

y^{^{'}} = 0.05 y + 5500

x \to 0 lim (1 - \frac{cos ( 3 x )}{x})

y = lo g_{2} (x), (32, 5)

\int (x^{3} + x) d x

\int (18 x^{2} + 3) (6 x^{3} + 3 x)^{6} d x

What is the integral of (3x)/(x+2) ?
The integral of (3x)/(x+2) is 3(x+2-2ln|x+2|)+C