What is the solution for y^'=0.05y+5500 ?

The solution for y^'=0.05y+5500 is y=20e^{(t+c_{1})/(20)}-110000

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=0.05y+5500

y^{^{'}} = 0.05 y + 5500

y = 20 e^{\frac{t + c _{1}}{20}} - 110000

Solution steps

y^{'} (t) = 0.05 y + 5500

Solve separable ODE:

y = 20 e^{\frac{t + c _{1}}{20}} - 110000

y = 20 e^{\frac{t + c _{1}}{20}} - 110000

x \to 0 lim (1 - \frac{cos ( 3 x )}{x})

y = lo g_{2} (x), (32, 5)

\int (x^{3} + x) d x

\int (18 x^{2} + 3) (6 x^{3} + 3 x)^{6} d x

\int \frac{2 x + 1}{( x + 1 ) ^{3} \cdot ( x ^{2} + 4 ) ^{2}} d x

What is the solution for y^'=0.05y+5500 ?
The solution for y^'=0.05y+5500 is y=20e^{(t+c_{1})/(20)}-110000