What is the solution for 2y^{'''}+3y^{''}-23y^'-12y=0 ?

The solution for 2y^{'''}+3y^{''}-23y^'-12y=0 is y=c_{1}e^{3t}+c_{2}e^{-t/2}+c_{3}e^{-4t}

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2y^{'''}+3y^{''}-23y^'-12y=0

2 y^{^{'''}} + 3 y^{^{''}} - 23 y^{^{'}} - 12 y = 0

y = c_{1} e^{3 t} + c_{2} e^{- \frac{t}{2}} + c_{3} e^{- 4 t}

Solution steps

2 y^{'''} (t) + 3 y^{''} (t) - 23 y^{'} (t) - 12 y = 0

Solve linear ODE:

y = c_{1} e^{3 t} + c_{2} e^{- \frac{t}{2}} + c_{3} e^{- 4 t}

y = c_{1} e^{3 t} + c_{2} e^{- \frac{t}{2}} + c_{3} e^{- 4 t}

\int x sin (10 x) d x

\int 0.4 t d t

x \to 0 lim (x^{2} - 4 x + 2)

\int 4 e^{2 x} + 3 d x

\frac{\partial}{\partial x} (\frac{( x y )}{( x - y )})

What is the solution for 2y^{'''}+3y^{''}-23y^'-12y=0 ?
The solution for 2y^{'''}+3y^{''}-23y^'-12y=0 is y=c_{1}e^{3t}+c_{2}e^{-t/2}+c_{3}e^{-4t}