What is the limit as x approaches 0 of x^2-4x+2 ?

The limit as x approaches 0 of x^2-4x+2 is 2

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limit as x approaches 0 of x^2-4x+2

x \to 0 lim (x^{2} - 4 x + 2)

2

Solution steps

x \to 0 lim (x^{2} - 4 x + 2)

Plug in the value

x = 0

= 0^{2} - 4 \cdot 0 + 2

Simplify

= 2

\int 4 e^{2 x} + 3 d x

\frac{\partial}{\partial x} (\frac{( x y )}{( x - y )})

x \to 0 lim (x + ln (x))

y^{^{''}} + 2 y^{^{'}} + y = 16 e - t

\frac{d}{d y} (y cos (x y))

What is the limit as x approaches 0 of x^2-4x+2 ?
The limit as x approaches 0 of x^2-4x+2 is 2