What is the integral from 0 to x of sin(x) ?

The integral from 0 to x of sin(x) is -cos(x)+1

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integral from 0 to x of sin(x)

\int_{0}^{x} sin (x) d x

- cos (x) + 1

Solution steps

\int_{0}^{x} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{0}^{x}

Compute the boundaries:

- cos (x) + 1

= - cos (x) + 1

\frac{\partial}{\partial x} (2 y x^{2} - 3)

f (x) = x^{2} - 3 x + 2

\int_{0}^{1} 7 x e^{- x^{2}} d x

\frac{\partial}{\partial x} (x y^{2} + 7)

\frac{d}{d x} (\frac{6 x ^{4}}{x ^{2} - 3})

What is the integral from 0 to x of sin(x) ?
The integral from 0 to x of sin(x) is -cos(x)+1