What is (\partial)/(\partial x)(xy^2+7) ?

The answer to (\partial)/(\partial x)(xy^2+7) is y^2

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(\partial)/(\partial x)(xy^2+7)

\frac{\partial}{\partial x} (x y^{2} + 7)

y^{2}

Solution steps

\frac{\partial}{\partial x} (x y^{2} + 7)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x y^{2}) + \frac{\partial}{\partial x} (7)

\frac{\partial}{\partial x} (x y^{2}) = y^{2}

\frac{\partial}{\partial x} (7) = 0

= y^{2} + 0

Simplify

= y^{2}

\frac{d}{d x} (\frac{6 x ^{4}}{x ^{2} - 3})

f (x) = cos (2 \cdot x) \cdot sin (5 \cdot x)

\frac{d}{d x} (\frac{x ^{4} - 1}{x ^{4} + 1})

\frac{d}{d x} ((x^{4} - 3 x^{2} + 5)^{3})

n = 1 \sum \infty \frac{n}{( 2 n ) !}

What is (\partial)/(\partial x)(xy^2+7) ?
The answer to (\partial)/(\partial x)(xy^2+7) is y^2