What is (\partial)/(\partial v)(3usin(v)) ?

The answer to (\partial)/(\partial v)(3usin(v)) is 3ucos(v)

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(\partial)/(\partial v)(3usin(v))

\frac{\partial}{\partial v} (3 u sin (v))

3 u cos (v)

Solution steps

\frac{\partial}{\partial v} (3 u sin (v))

Treat

u

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 u \frac{\partial}{\partial v} (sin (v))

Apply the common derivative:

\frac{\partial}{\partial v} (sin (v)) = cos (v)

= 3 u cos (v)

\frac{d y}{d x} + y^{3} x + 6 y = 0

x \to 0 lim (cos (2 x))

\int_{y}^{x} cos (t^{3}) d t

\frac{d}{d x} (4 - 2 sin (x))

\int 1 - \frac{1}{x + 1} d x

What is (\partial)/(\partial v)(3usin(v)) ?
The answer to (\partial)/(\partial v)(3usin(v)) is 3ucos(v)