What is the derivative of f(x)=2x^3-3x^2-36x+5 ?

The derivative of f(x)=2x^3-3x^2-36x+5 is 6x^2-6x-36

What is the first derivative of f(x)=2x^3-3x^2-36x+5 ?

The first derivative of f(x)=2x^3-3x^2-36x+5 is 6x^2-6x-36

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derivative of

f (x) = 2 x^{3} - 3 x^{2} - 36 x + 5

6 x^{2} - 6 x - 36

Solution steps

\frac{d}{d x} (2 x^{3} - 3 x^{2} - 36 x + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (36 x) + \frac{d}{d x} (5)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (36 x) = 36

\frac{d}{d x} (5) = 0

= 6 x^{2} - 6 x - 36 + 0

Simplify

= 6 x^{2} - 6 x - 36

f (x) = cos (a x)

x \to \infty + lim (ln (x))

\int π sin (π x) d x

\int \frac{1}{2 - 5 x} d x

e^{6 t}

What is the derivative of f(x)=2x^3-3x^2-36x+5 ?
The derivative of f(x)=2x^3-3x^2-36x+5 is 6x^2-6x-36
What is the first derivative of f(x)=2x^3-3x^2-36x+5 ?
The first derivative of f(x)=2x^3-3x^2-36x+5 is 6x^2-6x-36