What is laplacetransform f(x)=cos(ax) ?

The answer to laplacetransform f(x)=cos(ax) is s/(s^2+a^2)

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laplacetransform f(x)=cos(ax)

laplace transform

f (x) = cos (a x)

\frac{s}{s ^{2} + a ^{2}}

Solution steps

L {cos (a x)}

Use Laplace Transform table:

L {cos (a t)} = \frac{s}{s ^{2} + a ^{2}}

L {cos (a x)} = \frac{s}{s ^{2} + a ^{2}}

= \frac{s}{s ^{2} + a ^{2}}

x \to \infty + lim (ln (x))

\int π sin (π x) d x

\int \frac{1}{2 - 5 x} d x

e^{6 t}

f (x) = \frac{1}{x - 2}, (- 2, - \frac{1}{4})

What is laplacetransform f(x)=cos(ax) ?
The answer to laplacetransform f(x)=cos(ax) is s/(s^2+a^2)