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Popular >

integral of 1/(t+2)

Solution

\int \frac{1}{t + 2} d t

Solution

ln ∣ t + 2 ∣ + C

Solution steps

\int \frac{1}{t + 2} d t

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = t + 2

= ln ∣ t + 2 ∣

Add a constant to the solution

= ln ∣ t + 2 ∣ + C

Popular Examples

integral from-1 to 2 of x^2e^{x^3+1}

\int_{- 1}^{2} x^{2} e^{x^{3} + 1} d x

f(x)=ln(sec(x))

f (x) = ln (sec (x))

integral from 1 to x of t^4

\int_{1}^{x} t^{4} d t

derivative of f(x)=(x^2-2)^2 derivative of

f (x) = (x^{2} - 2)^{2}

derivative of ln(3x^2+2x)

\frac{d}{d x} (ln (3 x^{2} + 2 x))

Frequently Asked Questions (FAQ)

What is the integral of 1/(t+2) ?
The integral of 1/(t+2) is ln|t+2|+C