(\partial)/(\partial x)(ln(x+1))

解答

\frac{\partial}{\partial x} (ln (x + 1))

\frac{1}{x + 1}

求解步骤

\frac{\partial}{\partial x} (ln (x + 1))

使用连锁律:

\frac{1}{x + 1} \frac{\partial}{\partial x} (x + 1)

= \frac{1}{x + 1} \frac{\partial}{\partial x} (x + 1)

\frac{\partial}{\partial x} (x + 1) = 1

= \frac{1}{x + 1} \cdot 1

化简

= \frac{1}{x + 1}

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