What is the derivative of f(x)=6^xlog_{5}(x) ?

The derivative of f(x)=6^xlog_{5}(x) is (6^x+ln(6)*6^xxln(x))/(ln(5)x)

What is the first derivative of f(x)=6^xlog_{5}(x) ?

The first derivative of f(x)=6^xlog_{5}(x) is (6^x+ln(6)*6^xxln(x))/(ln(5)x)

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derivative of

f (x) = 6^{x} lo g_{5} (x)

\frac{6 ^{x} + ln ( 6 ) \cdot 6 ^{x} x ln ( x )}{ln ( 5 ) x}

Solution steps

\frac{d}{d x} (6^{x} lo g_{5} (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 6^{x}, g = lo g_{5} (x)

= \frac{d}{d x} (6^{x}) lo g_{5} (x) + \frac{d}{d x} (lo g_{5} (x)) 6^{x}

\frac{d}{d x} (6^{x}) = 6^{x} ln (6)

\frac{d}{d x} (lo g_{5} (x)) = \frac{1}{x ln ( 5 )}

= 6^{x} ln (6) lo g_{5} (x) + \frac{1}{x ln ( 5 )} \cdot 6^{x}

Simplify

6^{x} ln (6) lo g_{5} (x) + \frac{1}{x ln ( 5 )} \cdot 6^{x} : \frac{6 ^{x} + ln ( 6 ) \cdot 6 ^{x} x ln ( x )}{ln ( 5 ) x}

= \frac{6 ^{x} + ln ( 6 ) \cdot 6 ^{x} x ln ( x )}{ln ( 5 ) x}

\int_{0}^{2 π} cos^{2} (x) d x

\frac{\partial}{\partial y} (e^{3 x + 2 y})

\int \frac{4}{( x + 1 ) ^{2}} d x

\frac{d}{d x} (16 sin (2 x))

What is the derivative of f(x)=6^xlog_{5}(x) ?
The derivative of f(x)=6^xlog_{5}(x) is (6^x+ln(6)*6^xxln(x))/(ln(5)x)
What is the first derivative of f(x)=6^xlog_{5}(x) ?
The first derivative of f(x)=6^xlog_{5}(x) is (6^x+ln(6)*6^xxln(x))/(ln(5)x)