What is (\partial)/(\partial x)(sin(x)yz) ?

The answer to (\partial)/(\partial x)(sin(x)yz) is yzcos(x)

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(\partial)/(\partial x)(sin(x)yz)

\frac{\partial}{\partial x} (sin (x) yz)

yz cos (x)

Solution steps

\frac{\partial}{\partial x} (sin (x) yz)

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= yz \frac{\partial}{\partial x} (sin (x))

Apply the common derivative:

\frac{\partial}{\partial x} (sin (x)) = cos (x)

= yz cos (x)

5 sin (x - 0.64)

\int 7 16 - 2 x - 14 d x

x \to - 7 - lim (\frac{x + 6}{x + 7})

n = 1 \sum \infty (\frac{x}{2})^{n}

\int (x + 3) (x - 7) d x

What is (\partial)/(\partial x)(sin(x)yz) ?
The answer to (\partial)/(\partial x)(sin(x)yz) is yzcos(x)