What is the derivative of 5sin(x-0.64) ?

The derivative of 5sin(x-0.64) is 5(0.80209…cos(x)+0.59719…sin(x))

What is the first derivative of 5sin(x-0.64) ?

The first derivative of 5sin(x-0.64) is 5(0.80209…cos(x)+0.59719…sin(x))

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derivative of

5 sin (x - 0.64)

5 (0.80209 \dots cos (x) + 0.59719 \dots sin (x))

Solution steps

\frac{d}{d x} (5 sin (x - 0.64))

Simplify

5 sin (x - 0.64) : 5 (0.80209 \dots sin (x) - 0.59719 \dots cos (x))

= \frac{d}{d x} (5 (0.80209 \dots sin (x) - 0.59719 \dots cos (x)))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} (0.80209 \dots sin (x) - 0.59719 \dots cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= 5 (\frac{d}{d x} (0.80209 \dots sin (x)) - \frac{d}{d x} (0.59719 \dots cos (x)))

\frac{d}{d x} (0.80209 \dots sin (x)) = 0.80209 \dots cos (x)

\frac{d}{d x} (0.59719 \dots cos (x)) = - 0.59719 \dots sin (x)

= 5 (0.80209 \dots cos (x) - (- 0.59719 \dots sin (x)))

Simplify

= 5 (0.80209 \dots cos (x) + 0.59719 \dots sin (x))

\int 7 16 - 2 x - 14 d x

x \to - 7 - lim (\frac{x + 6}{x + 7})

n = 1 \sum \infty (\frac{x}{2})^{n}

\int (x + 3) (x - 7) d x

x^{2} - 3, 5 - x^{2}

What is the derivative of 5sin(x-0.64) ?
The derivative of 5sin(x-0.64) is 5(0.80209…cos(x)+0.59719…sin(x))
What is the first derivative of 5sin(x-0.64) ?
The first derivative of 5sin(x-0.64) is 5(0.80209…cos(x)+0.59719…sin(x))