What is the integral from-2 to 1 of (x-4|x|) ?

The integral from-2 to 1 of (x-4|x|) is -23/2

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integral from-2 to 1 of (x-4|x|)

\int_{- 2}^{1} (x - 4 ∣ x ∣) d x

- \frac{23}{2}

Solution steps

\int_{- 2}^{1} x - 4 ∣ x ∣ d x

Eliminate Absolutes

= \int_{- 2}^{0} x - 4 (- x) d x + \int_{0}^{1} x - 4 x d x

\int_{- 2}^{0} x - 4 (- x) d x = - 10

\int_{0}^{1} x - 4 x d x = - \frac{3}{2}

= - 10 - \frac{3}{2}

Simplify

- 10 - \frac{3}{2} : - \frac{23}{2}

= - \frac{23}{2}

y^{^{''}} - 4 y = e^{- 2 x} - 2 x

\int cos (10 x) cos (3 x) d x

f (x) = x + \frac{2}{x}, at x = 3

1500 e^{x}

What is the integral from-2 to 1 of (x-4|x|) ?
The integral from-2 to 1 of (x-4|x|) is -23/2