What is the tangent of f(x)=x+2/x ,\at x=3 ?

The tangent of f(x)=x+2/x ,\at x=3 is y= 7/9 x+4/3

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tangent of f(x)=x+2/x ,\at x=3

tangent of

f (x) = x + \frac{2}{x}, at x = 3

y = \frac{7}{9} x + \frac{4}{3}

Solution steps

Find the tangent point:

(3, \frac{11}{3})

Find the slope of

f (x) = x + \frac{2}{x} : \frac{df ( x )}{d x} = 1 - \frac{2}{x ^{2}}

Compute the slope of

f (x) = x + \frac{2}{x}

x = 3 : m = \frac{7}{9}

Find the line with slope m=

\frac{7}{9}

and passing through

(3, \frac{11}{3}) : y = \frac{7}{9} x + \frac{4}{3}

y = \frac{7}{9} x + \frac{4}{3}

1500 e^{x}

\frac{d}{d x} (\frac{x ^{2}}{x + 1})

y^{^{'}} + \frac{y}{t} = 2 cos (3 t)

\frac{d}{d x} (x^{2} (x - 1)^{3})

x \to 0 lim (\frac{( 2. 8 ^{x} - 1 )}{x})

What is the tangent of f(x)=x+2/x ,\at x=3 ?
The tangent of f(x)=x+2/x ,\at x=3 is y= 7/9 x+4/3