What is area y= 4/x ,y= 4/(x^2),x=5 ?

The answer to area y= 4/x ,y= 4/(x^2),x=5 is 4ln(5)-16/5

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area y= 4/x ,y= 4/(x^2),x=5

area

y = \frac{4}{x}, y = \frac{4}{x ^{2}}, x = 5

4 ln (5) - \frac{16}{5}

Solution steps

Apply the area formula:

\int_{1}^{5} \frac{4}{x} - \frac{4}{x ^{2}} d x

Solve

\int_{1}^{5} \frac{4}{x} - \frac{4}{x ^{2}} d x : 4 ln (5) - \frac{16}{5}

The area is:

= 4 ln (5) - \frac{16}{5}

\int 1 + \frac{1}{x} d x

\frac{d}{d x} (6 e^{5 x} + e^{- x^{2}})

x^{2}, 4 x - x^{2}

\int \frac{1}{25 e ^{- 4 x} + e ^{4 x}} d x

f (x) = (5 x^{6} + 2 x^{3})^{4}

What is area y= 4/x ,y= 4/(x^2),x=5 ?
The answer to area y= 4/x ,y= 4/(x^2),x=5 is 4ln(5)-16/5