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Popular >

y^'=2xe^y

Solution

y^{^{'}} = 2 x e^{y}

Solution

y = - ln (- x^{2} - c_{1})

Solution steps

y^{'} (x) = 2 x e^{y}

Solve separable ODE:

y = - ln (- x^{2} - c_{1})

y = - ln (- x^{2} - c_{1})

Popular Examples

(\partial)/(\partial x)(e^{xy}cos(bx+c))

\frac{\partial}{\partial x} (e^{x y} cos (b x + c))

(dy)/(dx)=2+sqrt(y-2x+4)

\frac{d y}{d x} = 2 + y - 2 x + 4

implicit (dy)/(dx),2xy=6 implicit derivative

\frac{d y}{d x}, 2 x y = 6

slope of (8.3)(3.5)slope

(8.3) (3.5)

integral of (x^2+4)^53x

\int (x^{2} + 4)^{5} 3 x d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=2xe^y ?
The solution for y^'=2xe^y is y=-ln(-x^2-c_{1})