What is the solution for (dy)/(dx)=2+sqrt(y-2x+4) ?

The solution for (dy)/(dx)=2+sqrt(y-2x+4) is y=(x^2+c_{1}^2)/4+(c_{1}x)/2+2x-4

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(dy)/(dx)=2+sqrt(y-2x+4)

\frac{d y}{d x} = 2 + y - 2 x + 4

y = \frac{x ^{2} + c _{1}^{2}}{4} + \frac{c _{1} x}{2} + 2 x - 4

Solution steps

\frac{d y}{d x} = 2 + y - 2 x + 4

Solve using substitution:

y = \frac{x ^{2} + c _{1}^{2}}{4} + \frac{c _{1} x}{2} + 2 x - 4

y = \frac{x ^{2} + c _{1}^{2}}{4} + \frac{c _{1} x}{2} + 2 x - 4

\frac{d y}{d x}, 2 x y = 6

(8.3) (3.5)

\int (x^{2} + 4)^{5} 3 x d x

\frac{\partial}{\partial x} (5 x^{2} - 3 x y + x yz)

- 2 t^{3}

What is the solution for (dy)/(dx)=2+sqrt(y-2x+4) ?
The solution for (dy)/(dx)=2+sqrt(y-2x+4) is y=(x^2+c_{1}^2)/4+(c_{1}x)/2+2x-4