What is the first derivative of 8x+6 ?

The first derivative of 8x+6 is 8

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derivative of 8x+6

\frac{d}{d x} (8 x + 6)

8

Solution steps

\frac{d}{d x} (8 x + 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 x) + \frac{d}{d x} (6)

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (6) = 0

= 8 + 0

Simplify

= 8

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