What is area y=x^4-3x^2+3,y=x^2 ?

The answer to area y=x^4-3x^2+3,y=x^2 is (112-24sqrt(3))/(15)

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area y=x^4-3x^2+3,y=x^2

area

y = x^{4} - 3 x^{2} + 3, y = x^{2}

\frac{112 - 24 3}{15}

Solution steps

Apply the area formula:

\int_{- 3}^{3} x^{4} - 4 x^{2} + 3 d x

Solve

\int_{- 3}^{3} x^{4} - 4 x^{2} + 3 d x : \frac{112 - 24 3}{15}

The area is:

= \frac{112 - 24 3}{15}

y = 5 x^{2} - x^{3}, (1, 4)

x \to 2 lim (\frac{2}{x})

\int 8 x + cos (x) d x

e^{3 x}, 9

What is area y=x^4-3x^2+3,y=x^2 ?
The answer to area y=x^4-3x^2+3,y=x^2 is (112-24sqrt(3))/(15)