What is the d/(dv)((\sqrt[3]{v}-2ve^v)/v) ?

The d/(dv)((\sqrt[3]{v}-2ve^v)/v) is (-6e^vv^2+v^{1/3}-3\sqrt[3]{v})/(3v^2)

What is the first d/(dv)((\sqrt[3]{v}-2ve^v)/v) ?

The first d/(dv)((\sqrt[3]{v}-2ve^v)/v) is (-6e^vv^2+v^{1/3}-3\sqrt[3]{v})/(3v^2)

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Solution steps

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

\frac{d v}{d v} = 1

Simplify

y = 5 x^{2} - x^{3}, (1, 4)

x \to 2 lim (\frac{2}{x})

\int 8 x + cos (x) d x

e^{3 x}, 9

\frac{\partial}{\partial x} (sin (x) cos (4 y))

What is the d/(dv)((\sqrt[3]{v}-2ve^v)/v) ?
The d/(dv)((\sqrt[3]{v}-2ve^v)/v) is (-6e^vv^2+v^{1/3}-3\sqrt[3]{v})/(3v^2)
What is the first d/(dv)((\sqrt[3]{v}-2ve^v)/v) ?
The first d/(dv)((\sqrt[3]{v}-2ve^v)/v) is (-6e^vv^2+v^{1/3}-3\sqrt[3]{v})/(3v^2)