What is the derivative of g(t)=sqrt(t) ?

The derivative of g(t)=sqrt(t) is 1/(2sqrt(t))

What is the first derivative of g(t)=sqrt(t) ?

The first derivative of g(t)=sqrt(t) is 1/(2sqrt(t))

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derivative of

g (t) = t

\frac{1}{2 t}

Solution steps

\frac{d}{d t} (t)

Apply radical rule:

a = a^{\frac{1}{2}}

= \frac{d}{d t} (t^{\frac{1}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{2} t^{\frac{1}{2} - 1}

Simplify

\frac{1}{2} t^{\frac{1}{2} - 1} : \frac{1}{2 t}

= \frac{1}{2 t}

\int \frac{ln ( 4 x )}{x ^{2}} d x

\frac{\partial}{\partial y} (y ln (y) - e^{- x y})

\int \frac{3 x + 1}{x ^{2} - 10 x + 28} d x

200 (e)^{0.03 x}

y = x^{4} - 3 x^{2} + 3, y = x^{2}

What is the derivative of g(t)=sqrt(t) ?
The derivative of g(t)=sqrt(t) is 1/(2sqrt(t))
What is the first derivative of g(t)=sqrt(t) ?
The first derivative of g(t)=sqrt(t) is 1/(2sqrt(t))