What is the derivative of 1+sin^2(x) ?

The derivative of 1+sin^2(x) is sin(2x)

What is the first derivative of 1+sin^2(x) ?

The first derivative of 1+sin^2(x) is sin(2x)

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\frac{d}{d x} (1 + sin^{2} (x))

sin (2 x)

Solution steps

\frac{d}{d x} (1 + sin^{2} (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (sin^{2} (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (sin^{2} (x)) = sin (2 x)

= 0 + sin (2 x)

Simplify

= sin (2 x)

(2 t + 4) i + sin (4 t) j + 2 t^{3} k

x \to 0 + lim (x^{3 x})

y = \frac{2}{x}

y = \frac{13}{ln ( x )}

\int sin (t) cos^{2} (t) d t

What is the derivative of 1+sin^2(x) ?
The derivative of 1+sin^2(x) is sin(2x)
What is the first derivative of 1+sin^2(x) ?
The first derivative of 1+sin^2(x) is sin(2x)